spopt.locate.LSCPB¶
- class spopt.locate.LSCPB(name: str, problem: LpProblem, solver: LpSolver)[source]¶
Implement the Location Set Covering Problem - Backup (LSCP-B) optimization model and solve it. The LSCP-B, as adapted from [CM18], can be formulated as:
\[\begin{split}\begin{array}{lllll} \displaystyle \textbf{Maximize} & \displaystyle \sum_{i \in I}{U_i} && & (1) \\ \displaystyle \textbf{Subject To} & \displaystyle \sum_{j \in J}{a_{ij}}{Y_j} \geq 1 + U_i && \forall i \in I & (2) \\ & \displaystyle \sum_{j \in J}{Y_j} = p && & (3) \\ & U_i \leq 1 && \forall i \in I & (4) \\ & Y_j \in \{0, 1\} && \forall j \in J & (5) \\ & && & \\ \displaystyle \textbf{Where} && i & = & \textrm{index of demand points/areas/objects in set } I \\ && j & = & \textrm{index of potential facility sites in set } J \\ && p & = & \textrm{objective value identified by using the } LSCP \\ && U_i & = & \begin{cases} 1, \textrm{if demand location is covered twice} \\ 0, \textrm{if demand location is covered once} \\ \end{cases} \\ && a_{ij} & = & \begin{cases} 1, \textrm{if facility location } j \textrm{ covers demand location } i \\ 0, \textrm{otherwise} \\ \end{cases} \\ && Y_j & = & \begin{cases} 1, \textrm{if a facility is sited at location } j \\ 0, \textrm{otherwise} \\ \end{cases} \end{array}\end{split}\]- Parameters:
- name
str
The problem name.
- problem
pulp.LpProblem
A
pulp
instance of an optimization model that contains constraints, variables, and an objective function.- solver
pulp.LpSolver
A solver supported by
pulp
.
- name
- Attributes:
- name
str
The problem name.
- problem
pulp.LpProblem
A
pulp
instance of an optimization model that contains constraints, variables, and an objective function.- solver
pulp.LpSolver
A solver supported by
pulp
.- lscp_obj_value
float
The objective value returned from a solved
LSCP
instance.- fac2cli
numpy.array
A 2D array storing facility to client relationships where each row represents a facility and contains an array of client indices with which it is associated. An empty client array indicates the facility is associated with no clients.
- cli2fac
numpy.array
The inverse of
fac2cli
where client to facility relationships are shown.- aij
numpy.array
A cost matrix in the form of a 2D array between origins and destinations.
- name
- __init__(name: str, problem: LpProblem, solver: LpSolver)[source]¶
Initialize.
- Parameters:
- name
str
The desired name for the model.
- name
Methods
__init__
(name, problem, solver)Initialize.
check_status
()Ensure a model is solved.
client_facility_array
()Create a 2D array storing client to facility relationships where each row represents a client and contains an array of facility indices with which it is associated.
Create a 2D array storing facility to client relationships where each row represents a facility and contains an array of client indices with which it is associated.
from_cost_matrix
(cost_matrix, ...[, ...])Create an
LSCPB
object based on a cost matrix.from_geodataframe
(gdf_demand, gdf_fac, ...)Create an
LSCPB
object fromgeopandas.GeoDataFrame
objects.get_percentage
()Calculate the percentage of clients with backup.
solve
([results])Solve the
LSCPB
model.- facility_client_array() None [source]¶
Create a 2D array storing facility to client relationships where each row represents a facility and contains an array of client indices with which it is associated. An empty client array indicates the facility is associated with no clients.
- Returns:
- classmethod from_cost_matrix(cost_matrix: array, service_radius: float, solver: LpSolver, predefined_facilities_arr: array = None, name: str = 'lscp-b')[source]¶
Create an
LSCPB
object based on a cost matrix.- Parameters:
- cost_matrix
numpy.array
A cost matrix in the form of a 2D array between origins and destinations.
- service_radius
float
Maximum acceptable service distance.
- solver
pulp.LpSolver
A solver supported by
pulp
.- predefined_facilities_arr
numpy.array
(defaultNone
) A binary 1D array of service facilities that must appear in the solution. For example, consider 3 facilites
['A', 'B', 'C']
. If facility'B'
must be in the model solution, then the passed in array should be[0, 1, 0]
.- name
str
(default ‘lscp-b’) The problem name.
- cost_matrix
- Returns:
Examples
>>> from spopt.locate import LSCPB >>> from spopt.locate.util import simulated_geo_points >>> import geopandas >>> import numpy >>> import pulp >>> import spaghetti
Create a regular lattice.
>>> lattice = spaghetti.regular_lattice((0, 0, 10, 10), 9, exterior=True) >>> ntw = spaghetti.Network(in_data=lattice) >>> streets = spaghetti.element_as_gdf(ntw, arcs=True) >>> streets_buffered = geopandas.GeoDataFrame( ... geopandas.GeoSeries(streets["geometry"].buffer(0.2).unary_union), ... crs=streets.crs, ... columns=["geometry"] ... )
Simulate points about the lattice.
>>> demand_points = simulated_geo_points(streets_buffered, needed=100, seed=5) >>> facility_points = simulated_geo_points(streets_buffered, needed=5, seed=6)
Snap the points to the network of lattice edges.
>>> ntw.snapobservations(demand_points, "clients", attribute=True) >>> clients_snapped = spaghetti.element_as_gdf( ... ntw, pp_name="clients", snapped=True ... ) >>> ntw.snapobservations(facility_points, "facilities", attribute=True) >>> facilities_snapped = spaghetti.element_as_gdf( ... ntw, pp_name="facilities", snapped=True ... )
Calculate the cost matrix from origins to destinations.
>>> cost_matrix = ntw.allneighbordistances( ... sourcepattern=ntw.pointpatterns["clients"], ... destpattern=ntw.pointpatterns["facilities"] ... )
Create and solve an
LSCPB
instance from the cost matrix.>>> lscpb_from_cost_matrix = LSCPB.from_cost_matrix( ... cost_matrix, service_radius=8, solver=pulp.PULP_CBC_CMD(msg=False) ... ) >>> lscpb_from_cost_matrix = lscpb_from_cost_matrix.solve()
Get the facility lookup demand coverage array.
>>> for fac, cli in enumerate(lscpb_from_cost_matrix.fac2cli): ... print(f"facility {fac} serving {len(cli)} clients") facility 0 serving 0 clients facility 1 serving 63 clients facility 2 serving 85 clients facility 3 serving 92 clients facility 4 serving 0 clients
Get the percentage of clients covered by more than one facility.
>>> round(lscpb_from_cost_matrix.backup_perc, 3) 88.0
88% of clients are covered by more than 1 facility
- classmethod from_geodataframe(gdf_demand: GeoDataFrame, gdf_fac: GeoDataFrame, demand_col: str, facility_col: str, service_radius: float, solver: LpSolver, predefined_facility_col: str = None, distance_metric: str = 'euclidean', name: str = 'lscp-b')[source]¶
Create an
LSCPB
object fromgeopandas.GeoDataFrame
objects. Calculate the cost matrix between demand and facility locations before building the problem within thefrom_cost_matrix()
method.- Parameters:
- gdf_demand
geopandas.GeoDataFrame
Demand locations.
- gdf_fac
geopandas.GeoDataFrame
Facility locations.
- demand_col
str
Demand sites geometry column name.
- facility_col
str
Facility candidate sites geometry column name.
- service_radius
float
Maximum acceptable service distance.
- solver
pulp.LpSolver
A solver supported by
pulp
.- predefined_facility_col
str
(defaultNone
) Column name representing facilities are already defined. This a binary assignment per facility. For example, consider 3 facilites
['A', 'B', 'C']
. If facility'B'
must be in the model solution, then the column should be[0, 1, 0]
.- distance_metric
str
(default ‘euclidean’) A metric used for the distance calculations supported by scipy.spatial.distance.cdist.
- name
str
(default ‘lscp-b’) The name of the problem.
- gdf_demand
- Returns:
Examples
>>> from spopt.locate import LSCPB >>> from spopt.locate.util import simulated_geo_points >>> import geopandas >>> import numpy >>> import pulp >>> import spaghetti
Create a regular lattice.
>>> lattice = spaghetti.regular_lattice((0, 0, 10, 10), 9, exterior=True) >>> ntw = spaghetti.Network(in_data=lattice) >>> streets = spaghetti.element_as_gdf(ntw, arcs=True) >>> streets_buffered = geopandas.GeoDataFrame( ... geopandas.GeoSeries(streets["geometry"].buffer(0.2).unary_union), ... crs=streets.crs, ... columns=["geometry"] ... )
Simulate points about the lattice.
>>> demand_points = simulated_geo_points(streets_buffered, needed=100, seed=5) >>> facility_points = simulated_geo_points(streets_buffered, needed=5, seed=6)
Snap the points to the network of lattice edges and extract as
GeoDataFrame
objects.>>> ntw.snapobservations(demand_points, "clients", attribute=True) >>> clients_snapped = spaghetti.element_as_gdf( ... ntw, pp_name="clients", snapped=True ... ) >>> ntw.snapobservations(facility_points, "facilities", attribute=True) >>> facilities_snapped = spaghetti.element_as_gdf( ... ntw, pp_name="facilities", snapped=True ... )
Create and solve an
LSCPB
instance from theGeoDataFrame
objects.>>> lscpb_from_geodataframe = LSCPB.from_geodataframe( ... clients_snapped, ... facilities_snapped, ... "geometry", ... "geometry", ... service_radius=8, ... solver=pulp.PULP_CBC_CMD(msg=False), ... distance_metric="euclidean" ... ) >>> lscpb_from_geodataframe = lscpb_from_geodataframe.solve()
Get the facility lookup demand coverage array.
>>> for fac, cli in enumerate(lscpb_from_geodataframe.fac2cli): ... print(f"facility {fac} serving {len(cli)} clients") facility 0 serving 0 clients facility 1 serving 0 clients facility 2 serving 100 clients facility 3 serving 0 clients facility 4 serving 0 clients
Get the percentage of clients covered by more than one facility.
>>> round(lscpb_from_geodataframe.backup_perc, 3) 0.0
All clients are covered by 1 facility because only one facility is needed to solve the LSCP.